[Solved]1 Following Options Checks City Neither Chicago Dallas City Chicago City Dallas City Chica Q37208144

1.Which of the following options checks that city is neitherChicago nor Dallas?

if (city != “Chicago” || city != “Dallas”)

if !(city == “Chicago” || city == “Dallas”)

if !(city == “Chicago” && city == “Dallas”)

if (city != “Chicago” || city == “Dallas”)

2.What is the value of the cost variable after the followingcode snippet is executed?

int cost = 82;if (cost < 100) { cost = cost + 10; }if (cost > 50) { cost = cost * 2; }if (cost < 100) { cost = cost – 20; }

82

92

184

164

3.What is the value of the price variable after the followingcode snippet is executed?

int price = 42;if (price < 40) { price = price + 10; }if (price > 30) { price = price * 2; }if (price < 100) { price = price – 20; }

42

52

84

64

4.A store provides 10% discount on all items with a price of atleast $100. No discount is otherwise applicable. Which of thefollowing statements DOES NOT correctly compute the discount?

double discount = 0; if (price >= 100) { discount = 0.10 * price; }double discount = 0.10 * price; if (price <= 100) { discount = 0; }double discount; if (price < 100) { discount = 0; } else { discount = 0.10 * price; }double discount = 10; if (price >= 100) discount = 0.1 * price; else discount = 0;

5.Which condition, when supplied in the if statement below inplace of (. . .), will correctly protect against division byzero?

if (. . .){ result = grade / num; cout << “Just avoided division by zero!” << endl;}

(grade == 0)

((grade / num) == 0)

(num == 0)

(num != 0)

6.In a switch statement, if a break statement is missing

The break happens at the end of each branch by default

The statement will not compile

Execution falls through the next branch until a break statementis reached

The default case is automatically executed

Expert Answer

---

Answer to 1.Which of the following options checks that city is neither Chicago nor Dallas? if (city != “Chicago” || city != “Dalla… . . .